Java String Manipulation
Java provides the String class that contains a lot of useful methods to
operate on strings. For example, you can use Java string operations methods to find
the length of a string, get a character in a specified index of a string,
combine two strings,
change cases of a string to lower case or upper case, find the position
of a character or a substring in another string, convert a string
to an array of character, get a substring
from a string, compare two strings, test a string whether it starts with
or ends with a substring, and replace an existing substring with a new
substring in a string.
The Java string operation methods that can handle those such things can
be length(), charAt(), concat(), toLowerCase, toUpperCase, indexOf(),
toCharArray(), substring(), compareTo(), equals(), startsWith(), endsWith(),
and replace() methods.
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Java programming tutorial
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 Posted comments | Phan Neth, CICI, year 3: Now it is ok teacher. I can connect to database and select data from it. Than you so much teacher !!!!!
04-30-2013 | Dara: Copy and paste the link below to the address box to learn how to connect C and Mysql server:
http://www.worldbestlearningcenter.com/index_files/cpp-tutorial-connect_mysql_database.htm
04-27-2013 | Phan Neth, CICI, year 3: Hello teacher i want to connect C programming language to MySql server but it have problem. When i compile it always error with library " my_global.h
and mysql.h", so how should i do?
04-27-2013 | Phan Neth, Year 3 at CICI,: I have some problem about connection to mysql server. So I hope teacher can help me. Thank !!!!
04-26-2013 | Federico: Output appears the same also this way:
static void Main(string[] args)
{
int[,] myArray = new int[5, 5];
int row, i;
int n = 1;
for (row = 0; row < 5; row++)
{
for (i = 0; i < 5; i++)
{
myArray[row, i] = n;
if (row == 1 && i == 2) Console.Write(" \t");
else Console.Write("{0} \t", n);
if (n!=26) n++;
if((i+1)%5==0) Console.WriteLine("\n");
}
}
Console.ReadLine();
}
04-13-2013 | Dara: Let pointer p point to the index 1 elem (value=2) of the array.
int *p= a+1;
Let pointer q point to the index 6 elem (value=5) of the array.
int *q= a+6;
-Expression q-p is the subtraction of address of the index 6 element and the address of index 1 elem of the array. So, the result is 5.
-Expression *p+*q is the sum of the value of index 1 elem (2) and the value of index 6 elem (5). So, the result is 7.
In conclusion, the output is 57.
03-28-2013 | Anushka : Find the output of following code
main()
{
int a[] = {1,2,9,8,6,3,5,7,8,9};
int *p= a+1; int *q= a+6;
cout<< q-p <<*p+*q; }
03-28-2013 | Dara: Option Explicit
Dim Cn as New ADODB.Connection
Private Sub_Form_Load()
Cn.Open "Provider=SQLOLEDB; Data Source=ServerName; Initial Catalog=DatabaseName;UserID=UserName; Password=Passw"
End Sub
You will need to replace ServerName with the name of your server (installed SQL Server), DatabaseName withe the name of your data file that you want to connect to, UserName with the name of the user to login to SQL Server, and Passw with the password used to login to SQL Server.
03-13-2013 | More>>> |
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