C++ OOP: doubly linked list

Max and Min elements of doubly linked list

Step 5: Showing the minimum and maximum items

To find the minimum item of the doubly linked list, you need to compare each item of the list by allowing a min variable to point to the first item of the list then starting to compare its data with its next item. If the data of its next item is less than the data of the min, simply allow the min to catch the next item.

//Find min item

public ListNode<T> findmin()

       {

             ListNode<T> t, min;

             t = pfirst;

             min = t;

             while (t != null)

              {

                 if (t.val.ToString().CompareTo(min.val.ToString()) < 0) min = t;

                 t = t.next;

                }

                return min;

            }

 

Finding the maximum item of the doubly linked list can be done similarly as finding the minimum item. You need to compare each item of the list by allowing a max variable to point to the first item of the list then starting to compare its data with its next item. If the data of its next item is greater than the data of the max, simply allow the max to catch the next item.


//Find max item

public ListNode<T> findmax()

            {

                ListNode<T> t, max;

                t = pfirst;

                max = t;

                while (t != null)

              {

                if (t.val.ToString().CompareTo(max.val.ToString()) > 0) max = t;

                t = t.next;

                }

                return max;

            }

        }




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