C++ exercises and solutions: series of numbers

 Kostandin

Can someone Help me please i have this exercise but different

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User inputs an integer N from the range from 1 to 30. Write a program to display the numbers from 1 to N*N in a table with N*N size in the following pattern
Input
3

Output
1 4 7
2 5 8
3 6 9

^^^^^^ if someone can solve it for me please send it to my email vllahukostandin@gmail.com

 Evan F

this seems simpler

#include <iostream>

using namespace std;

int main(int argc, const char * argv[]) {

int arr[5][5]={0};

int num=1;

//fill 2D array with integers
for(int i=0;i<5;i++){
for(int j=0;j<5;j++){

arr[i][j]=num;

num++;

}
}

//print array
for(int i=0;i<5;i++){
for(int j=0;j<5;j++){

cout<<arr[i][j]<<"\t";

}
cout<<"\n";
}

return 0;
}

 Mariano

I would replace

for(i=0;i<5;i++) //assign values to the two-dimensional array
for(j=0;j<=5;j++){
if(i==0) tArr[i][j]=j+1; //fill the first row
if(i>0 && j==0)

tArr[i][j]=tArr[i-1][4]+1; //fetching the value of the last cell in the previous row
else
tArr[i][j]=tArr[i][j-1]+1; //fill subsequent cells
}

With this:

for(i=0;i<5;i++) //assign values to the two-dimensional array
for(j=0;j<=5;j++){
tArr[i][j]= (j+1) + (i*5);
}